Optimal. Leaf size=146 \[ \frac{\left (8 a^2+b^2\right ) \sin (c+d x) \cos ^5(c+d x)}{48 d}+\frac{5 \left (8 a^2+b^2\right ) \sin (c+d x) \cos ^3(c+d x)}{192 d}+\frac{5 \left (8 a^2+b^2\right ) \sin (c+d x) \cos (c+d x)}{128 d}+\frac{5}{128} x \left (8 a^2+b^2\right )-\frac{9 a b \cos ^7(c+d x)}{56 d}-\frac{b \cos ^7(c+d x) (a+b \sin (c+d x))}{8 d} \]
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Rubi [A] time = 0.133561, antiderivative size = 146, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.19, Rules used = {2692, 2669, 2635, 8} \[ \frac{\left (8 a^2+b^2\right ) \sin (c+d x) \cos ^5(c+d x)}{48 d}+\frac{5 \left (8 a^2+b^2\right ) \sin (c+d x) \cos ^3(c+d x)}{192 d}+\frac{5 \left (8 a^2+b^2\right ) \sin (c+d x) \cos (c+d x)}{128 d}+\frac{5}{128} x \left (8 a^2+b^2\right )-\frac{9 a b \cos ^7(c+d x)}{56 d}-\frac{b \cos ^7(c+d x) (a+b \sin (c+d x))}{8 d} \]
Antiderivative was successfully verified.
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Rule 2692
Rule 2669
Rule 2635
Rule 8
Rubi steps
\begin{align*} \int \cos ^6(c+d x) (a+b \sin (c+d x))^2 \, dx &=-\frac{b \cos ^7(c+d x) (a+b \sin (c+d x))}{8 d}+\frac{1}{8} \int \cos ^6(c+d x) \left (8 a^2+b^2+9 a b \sin (c+d x)\right ) \, dx\\ &=-\frac{9 a b \cos ^7(c+d x)}{56 d}-\frac{b \cos ^7(c+d x) (a+b \sin (c+d x))}{8 d}+\frac{1}{8} \left (8 a^2+b^2\right ) \int \cos ^6(c+d x) \, dx\\ &=-\frac{9 a b \cos ^7(c+d x)}{56 d}+\frac{\left (8 a^2+b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{48 d}-\frac{b \cos ^7(c+d x) (a+b \sin (c+d x))}{8 d}+\frac{1}{48} \left (5 \left (8 a^2+b^2\right )\right ) \int \cos ^4(c+d x) \, dx\\ &=-\frac{9 a b \cos ^7(c+d x)}{56 d}+\frac{5 \left (8 a^2+b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{192 d}+\frac{\left (8 a^2+b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{48 d}-\frac{b \cos ^7(c+d x) (a+b \sin (c+d x))}{8 d}+\frac{1}{64} \left (5 \left (8 a^2+b^2\right )\right ) \int \cos ^2(c+d x) \, dx\\ &=-\frac{9 a b \cos ^7(c+d x)}{56 d}+\frac{5 \left (8 a^2+b^2\right ) \cos (c+d x) \sin (c+d x)}{128 d}+\frac{5 \left (8 a^2+b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{192 d}+\frac{\left (8 a^2+b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{48 d}-\frac{b \cos ^7(c+d x) (a+b \sin (c+d x))}{8 d}+\frac{1}{128} \left (5 \left (8 a^2+b^2\right )\right ) \int 1 \, dx\\ &=\frac{5}{128} \left (8 a^2+b^2\right ) x-\frac{9 a b \cos ^7(c+d x)}{56 d}+\frac{5 \left (8 a^2+b^2\right ) \cos (c+d x) \sin (c+d x)}{128 d}+\frac{5 \left (8 a^2+b^2\right ) \cos ^3(c+d x) \sin (c+d x)}{192 d}+\frac{\left (8 a^2+b^2\right ) \cos ^5(c+d x) \sin (c+d x)}{48 d}-\frac{b \cos ^7(c+d x) (a+b \sin (c+d x))}{8 d}\\ \end{align*}
Mathematica [A] time = 0.374819, size = 141, normalized size = 0.97 \[ \frac{840 \left (8 a^2+b^2\right ) (c+d x)+336 \left (15 a^2+b^2\right ) \sin (2 (c+d x))+168 \left (6 a^2-b^2\right ) \sin (4 (c+d x))+112 (a-b) (a+b) \sin (6 (c+d x))-3360 a b \cos (c+d x)-2016 a b \cos (3 (c+d x))-672 a b \cos (5 (c+d x))-96 a b \cos (7 (c+d x))-21 b^2 \sin (8 (c+d x))}{21504 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.043, size = 128, normalized size = 0.9 \begin{align*}{\frac{1}{d} \left ({b}^{2} \left ( -{\frac{\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{8}}+{\frac{\sin \left ( dx+c \right ) }{48} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{5}+{\frac{5\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{4}}+{\frac{15\,\cos \left ( dx+c \right ) }{8}} \right ) }+{\frac{5\,dx}{128}}+{\frac{5\,c}{128}} \right ) -{\frac{2\,ab \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{7}}+{a}^{2} \left ({\frac{\sin \left ( dx+c \right ) }{6} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{5}+{\frac{5\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{4}}+{\frac{15\,\cos \left ( dx+c \right ) }{8}} \right ) }+{\frac{5\,dx}{16}}+{\frac{5\,c}{16}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.975867, size = 154, normalized size = 1.05 \begin{align*} -\frac{6144 \, a b \cos \left (d x + c\right )^{7} + 112 \,{\left (4 \, \sin \left (2 \, d x + 2 \, c\right )^{3} - 60 \, d x - 60 \, c - 9 \, \sin \left (4 \, d x + 4 \, c\right ) - 48 \, \sin \left (2 \, d x + 2 \, c\right )\right )} a^{2} - 7 \,{\left (64 \, \sin \left (2 \, d x + 2 \, c\right )^{3} + 120 \, d x + 120 \, c - 3 \, \sin \left (8 \, d x + 8 \, c\right ) - 24 \, \sin \left (4 \, d x + 4 \, c\right )\right )} b^{2}}{21504 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.46034, size = 270, normalized size = 1.85 \begin{align*} -\frac{768 \, a b \cos \left (d x + c\right )^{7} - 105 \,{\left (8 \, a^{2} + b^{2}\right )} d x + 7 \,{\left (48 \, b^{2} \cos \left (d x + c\right )^{7} - 8 \,{\left (8 \, a^{2} + b^{2}\right )} \cos \left (d x + c\right )^{5} - 10 \,{\left (8 \, a^{2} + b^{2}\right )} \cos \left (d x + c\right )^{3} - 15 \,{\left (8 \, a^{2} + b^{2}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{2688 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 13.7406, size = 398, normalized size = 2.73 \begin{align*} \begin{cases} \frac{5 a^{2} x \sin ^{6}{\left (c + d x \right )}}{16} + \frac{15 a^{2} x \sin ^{4}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{16} + \frac{15 a^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{16} + \frac{5 a^{2} x \cos ^{6}{\left (c + d x \right )}}{16} + \frac{5 a^{2} \sin ^{5}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{16 d} + \frac{5 a^{2} \sin ^{3}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{6 d} + \frac{11 a^{2} \sin{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{16 d} - \frac{2 a b \cos ^{7}{\left (c + d x \right )}}{7 d} + \frac{5 b^{2} x \sin ^{8}{\left (c + d x \right )}}{128} + \frac{5 b^{2} x \sin ^{6}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{32} + \frac{15 b^{2} x \sin ^{4}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{64} + \frac{5 b^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{6}{\left (c + d x \right )}}{32} + \frac{5 b^{2} x \cos ^{8}{\left (c + d x \right )}}{128} + \frac{5 b^{2} \sin ^{7}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{128 d} + \frac{55 b^{2} \sin ^{5}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{384 d} + \frac{73 b^{2} \sin ^{3}{\left (c + d x \right )} \cos ^{5}{\left (c + d x \right )}}{384 d} - \frac{5 b^{2} \sin{\left (c + d x \right )} \cos ^{7}{\left (c + d x \right )}}{128 d} & \text{for}\: d \neq 0 \\x \left (a + b \sin{\left (c \right )}\right )^{2} \cos ^{6}{\left (c \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.10233, size = 219, normalized size = 1.5 \begin{align*} \frac{5}{128} \,{\left (8 \, a^{2} + b^{2}\right )} x - \frac{a b \cos \left (7 \, d x + 7 \, c\right )}{224 \, d} - \frac{a b \cos \left (5 \, d x + 5 \, c\right )}{32 \, d} - \frac{3 \, a b \cos \left (3 \, d x + 3 \, c\right )}{32 \, d} - \frac{5 \, a b \cos \left (d x + c\right )}{32 \, d} - \frac{b^{2} \sin \left (8 \, d x + 8 \, c\right )}{1024 \, d} + \frac{{\left (a^{2} - b^{2}\right )} \sin \left (6 \, d x + 6 \, c\right )}{192 \, d} + \frac{{\left (6 \, a^{2} - b^{2}\right )} \sin \left (4 \, d x + 4 \, c\right )}{128 \, d} + \frac{{\left (15 \, a^{2} + b^{2}\right )} \sin \left (2 \, d x + 2 \, c\right )}{64 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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